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10.5+7x-12x^2=0
a = -12; b = 7; c = +10.5;
Δ = b2-4ac
Δ = 72-4·(-12)·10.5
Δ = 553
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{553}}{2*-12}=\frac{-7-\sqrt{553}}{-24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{553}}{2*-12}=\frac{-7+\sqrt{553}}{-24} $
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